JavaScript POST提交数据并跳转

jQuery

    $.extend({
        StandardPost:function(url,args){
            console.log(args)
            var body = $(document.body),
                form = $("<form method='post'></form>"),
                input;
            form.attr({"action":url});
            $.each(args,function(key,value){
                input = $("<input type='hidden'>");
                input.attr({"name":key});
                input.val(value);
                form.append(input);
            });

            form.appendTo(document.body);
            form.submit();
            document.body.removeChild(form[0]);
        }
    });

via: https://segmentfault.com/q/1010000000473230